A large insulated sphere of radius r, charged with Q C is placed in contact with a small insulated uncharged sphere of radius r₁ and is then separated. The charge on the smaller sphere will now be (a) Q(r + r₁) (b) Q(r - r₁) (c) (Q)/((r + r₁)) (d) (Qr₁)/((r + r₁))

Answer: (d). In contact both spheres reach the same potential: (q₁)/(r₁) = q₂/r, so charge divides in proportion to radius. q₁ + q₂ = Q q₁ = (Q r₁)/(r + r₁) So the answer is (d).

A large insulated sphere of radius r, charged with Q C is placed in… | MHT CET 2026 (15 May, Shift 1)

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Electric Potential & Equipotentials

A large insulated sphere of radius $r$ , charged with $Q$ C is placed in contact with a small insulated uncharged sphere of radius $r_1$ and is then separated. The charge on the smaller sphere will now be

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Answer: (d)

In contact both spheres reach the same potential: $\dfrac{q_1}{r_1} = \dfrac{q_2}{r}$ , so charge divides in proportion to radius.
$q_1 + q_2 = Q$
$q_1 = \dfrac{Q r_1}{r + r_1}$
So the answer is (d).

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Electric Potential & Equipotentials question from MHT CET 2026 (15 May, Shift 1)

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