Physics Circle home Student Login

Home›Chapters›Surface Tension PYQs›Splitting & Merging of Drops›Question 49

JEE Main 2021 (26 Feb, Shift 1) · Splitting & Merging of Drops

Splitting & Merging of Drops question from JEE Main 2021 (26 Feb, Shift 1)

Q49JEE Main 2021 · 26 FEB · SHIFT 1Medium

Splitting & Merging of Drops

A large number of water drops, each of radius r, combine to have a drop of radius R. If the surface tension is T and mechanical equivalent of heat is J, the rise in heat energy per unit volume will be:

Show answer and solution

Answer: (b)

  1. Volume V=n⋅43πr3=43πR3V = n \cdot \frac{4}{3}\pi r^3 = \frac{4}{3}\pi R^3, so n⋅4πr2=3Vrn \cdot 4\pi r^2 = \frac{3V}{r} and 4πR2=3VR4\pi R^2 = \frac{3V}{R}.
  2. Energy released =T ΔA=3VT(1r−1R)= T\,\Delta A = 3VT\left(\frac{1}{r} - \frac{1}{R}\right)
  3. Heat per unit volume =3TJ(1r−1R)= \frac{3T}{J}\left(\frac{1}{r} - \frac{1}{R}\right)
  4. So the answer is (b).
Report a mistake

More questions on Splitting & Merging of Drops