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JEE Main 2024 (8 Apr, Shift 1) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from JEE Main 2024 (8 Apr, Shift 1)

Q42JEE Main 2024 · 8 APR · SHIFT 1Easy

Resonance, Bandwidth & Q Factor

A LCR circuit is at resonance for a capacitor C, inductance L and resistance R. Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now:

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Answer: (d)

At resonance $Z = R$ , so $I_0 = \dfrac{E_0}{R} \propto \dfrac{1}{R}$ ; $L$ and $C$ unchanged keep the same resonance.
$R \to \dfrac{R}{2} \Rightarrow I_0' = 2I_0$
So the answer is (d) double.

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