A lead bullet moving with velocity ' v ' strikes a wall and stops. 75% of its energy is converted into heat. If the increase in the temperature is (v²)/(nJs), then the value of n is s = specific heat of lead, J = mechanical equivalent of heat (a) 8/3 (b) 4/3 (c) 3/8 (d) 3/4

Answer: (a). 0.75 × 1/2mv² = J m s Δ T Δ T = (3v²)/(8Js) = (v²)/(8/3Js) So n = 8/3, answer (a).

A lead bullet moving with velocity ' v ' strikes a wall and stops… | MHT CET 2026 (19 May, Shift 2)

Q2MHT CET 2026 · 19 MAY · SHIFT 2Medium

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

A lead bullet moving with velocity ' $v$ ' strikes a wall and stops. $75\%$ of its energy is converted into heat. If the increase in the temperature is $\frac{v^2}{nJs}$ , then the value of $n$ is

$\{s =$ specific heat of lead $, J =$ mechanical equivalent of heat $\}$

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Answer: (a)

$0.75 \times \tfrac{1}{2}mv^2 = J\,m\,s\,\Delta T$
$\Delta T = \dfrac{3v^2}{8Js} = \dfrac{v^2}{\tfrac{8}{3}Js}$
So $n = \tfrac{8}{3}$ , answer (a).

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