Physics Circle home Student Login

Home›Chapters›Fluid Dynamics PYQs›Velocity of Efflux (Torricelli)›Question 20

JEE Main 2021 (27 Jul, Shift 1) · Velocity of Efflux (Torricelli)

Velocity of Efflux (Torricelli) question from JEE Main 2021 (27 Jul, Shift 1)

Q20JEE Main 2021 · 27 JUL · SHIFT 1Difficult

Velocity of Efflux (Torricelli)

A light cylindrical vessel is kept on a horizontal surface. Area of base is A. A hole of cross-sectional area 'a' is made just at its bottom side. The minimum coefficient of friction necessary to prevent sliding the vessel due to the impact force of the emerging liquid is (a < < A):

Figure

Show answer and solution

Answer: (c)

  1. Efflux speed v=2ghv = \sqrt{2gh}, so the jet's reaction force is F=ρav2=2ρaghF = \rho a v^2 = 2\rho a g h.
  2. Vessel is light, so normal force = weight of liquid: N=ρAhgN = \rho A h g.
  3. No sliding: μN≥F⇒μ≥2ρaghρAhg=2aA\mu N \ge F \Rightarrow \mu \ge \frac{2\rho a g h}{\rho A h g} = \frac{2a}{A}
  4. So the answer is (c) 2aA\frac{2a}{A}.
Report a mistake

More questions on Velocity of Efflux (Torricelli)