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MHT CET 2025 (20 Apr, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2025 (20 Apr, Shift 2)

Q36MHT CET 2025 · 20 APR · SHIFT 2Medium

Matter Waves: de Broglie Wavelength

A light of wavelength λ\lambda is incident on a photosensitive surface of negligible work function. The photoelectrons emitted from the surface have de-Broglie wavelength λ1\lambda_1. Then ratio λ:λ1 2\lambda : \lambda_1^{\,2} is ( h=\mathrm{h} = Planck's constant, c=\mathrm{c} = velocity of light, m=\mathrm{m} = mass of electron)

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Answer: (c)

  1. Negligible work function: hcλ=p22m=h22mλ12\dfrac{hc}{\lambda} = \dfrac{p^2}{2m} = \dfrac{h^2}{2m\lambda_1^2}.
  2. λ=2mchλ12⇒λλ12=2mch\lambda = \dfrac{2mc}{h}\lambda_1^2 \Rightarrow \dfrac{\lambda}{\lambda_1^2} = \dfrac{2mc}{h}
  3. So the answer is (c) 2mc:h2mc : h.
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