A light ray falls on a glass surface of refractive index √(3), at an angle 60 °. The angle between the refracted and reflected rays would be (a) 30 ° (b) 60 ° (c) 90 ° (d) 120 °

Answer: (c). Brewster angle: tan θB = μ = √(3) ⇒ θB = 60°. The given angle of incidence 60° equals θB. At Brewster's angle the reflected and refracted rays are perpendicular. So the answer is (c) 90°.

A light ray falls on a glass surface of refractive index √(3), at an… | NEET 2022 (Phase 1)

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Refraction, Glass Slab & Apparent Depth

A light ray falls on a glass surface of refractive index $\sqrt{3}$ , at an angle 60 ${}^\circ$ . The angle between the refracted and reflected rays would be

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Answer: (c)

Brewster angle: $\tan\theta_B = \mu = \sqrt{3} \Rightarrow \theta_B = 60^\circ$ .
The given angle of incidence $60^\circ$ equals $\theta_B$ .
At Brewster's angle the reflected and refracted rays are perpendicular.
So the answer is (c) $90^\circ$ .

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