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NEET 2016 (Phase 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from NEET 2016 (Phase 2)

Q175NEET 2016 · PHASE 2Medium

Moment of Inertia & Radius of Gyration

A light rod of length $l$ has two masses m1 and m2 attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is

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Answer: (a)

Distances from the CM: $r_1 = \frac{m_2 l}{m_1+m_2}$ , $r_2 = \frac{m_1 l}{m_1+m_2}$ .
$I = m_1r_1^2 + m_2r_2^2 = \frac{m_1m_2(m_2+m_1)l^2}{(m_1+m_2)^2}$
$I = \frac{m_1m_2}{m_1+m_2}l^2$ (reduced mass $\times l^2$ ), so the answer is (a).

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