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JEE Main 2023 (13 Apr, Shift 2) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from JEE Main 2023 (13 Apr, Shift 2)

Q24JEE Main 2023 · 13 APR · SHIFT 2Easy

Rotational Kinematics & Dynamics

A light rope is wound around a hollow cylinder of mass 5 kg and radius 70 cm. The rope is pulled with a force of 52.5 N. The angular acceleration of the cylinder will be _________ rad s−2-2.

Numerical answer type. Work it out, then open the answer.

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Answer: 15

  1. Hollow cylinder: I=MR2=5×0.72=2.45I = MR^2 = 5 \times 0.7^2 = 2.45 kg m2^2
  2. τ=FR=52.5×0.7=36.75\tau = FR = 52.5 \times 0.7 = 36.75 N m
  3. α=36.752.45=15\alpha = \frac{36.75}{2.45} = 15 rad s−2^{-2}
  4. So the answer is 15.
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