A light spring is suspended with mass ' m₁ ' at its lower end and its… | MHT CET 2026 (17 Apr, Shift 2)

Q10MHT CET 2026 · 17 APR · SHIFT 2Medium

Spring Systems

A light spring is suspended with mass ' $m_1$ ' at its lower end and its upper end is fixed to a rigid support. The mass is pulled down a short distance and then released. The period of oscillation is T second. When a mass ' ' is added to ' $m_1$ ' and the system is made to oscillate the period is found to be $\frac{3}{2}$ T. The ratio $m_2\ \left(\frac{m_1}{m_2}\right)$ is

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Answer: (c)

$T \propto \sqrt{m}$ : $\left(\frac{3}{2}\right)^2 = \frac{m_1+m_2}{m_1}$ .
$\frac{9}{4} = 1 + \frac{m_2}{m_1} \Rightarrow \frac{m_2}{m_1} = \frac{5}{4}$
$m_1 : m_2 = 4 : 5$ , so the answer is (c).

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Spring Systems question from MHT CET 2026 (17 Apr, Shift 2)

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