A light string passing over a smooth light fixed pulley connects two blocks of masses m₁ and m₂. If the acceleration of the system is g/8, then the ratio of masses is: (a) 8/1 (b) 9/7 (c) 5/3 (d) 4/3

Answer: (b). (m₂ - m₁)/(m₂ + m₁) = 1/8 ⇒ 8m₂ - 8m₁ = m₂ + m₁ 7m₂ = 9m₁ ⇒ (m₂)/(m₁) = 9/7 So the answer is (b) 9/7.

A light string passing over a smooth light fixed pulley connects two… | JEE Main 2024 (31 Jan, Shift 2)

Q15JEE Main 2024 · 31 JAN · SHIFT 2Easy

Connected Bodies & Pulleys

A light string passing over a smooth light fixed pulley connects two blocks of masses $m_1$ and $m_2$ . If the acceleration of the system is $g/8$ , then the ratio of masses is:

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Answer: (b)

$\dfrac{m_2 - m_1}{m_2 + m_1} = \dfrac{1}{8} \Rightarrow 8m_2 - 8m_1 = m_2 + m_1$
$7m_2 = 9m_1 \Rightarrow \dfrac{m_2}{m_1} = \dfrac{9}{7}$
So the answer is (b) $\dfrac{9}{7}$ .

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