Physics Circle home Student Login

Home›Chapters›Wave Optics PYQs›Diffraction at a Single Slit›Question 64

MHT CET 2020 (16 Oct, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from MHT CET 2020 (16 Oct, Shift 2)

Q64MHT CET 2020 · 16 OCT · SHIFT 2Easy

Diffraction at a Single Slit

A light wave of wavelength λ\lambda is incident on a slit of width dd. The resulting diffraction pattern is observed on a screen at a distance DD. If linear width of the principal maxima is equal to the width of the slit, then the distance DD is

Show answer and solution

Answer: (b)

  1. Linear width of principal maximum =2Dλd= \dfrac{2D\lambda}{d}.
  2. Equating to slit width: 2Dλd=d⇒D=d22λ\dfrac{2D\lambda}{d} = d \Rightarrow D = \dfrac{d^2}{2\lambda}.
  3. So the answer is (b) d22λ\dfrac{d^2}{2\lambda}.
Report a mistake

More questions on Diffraction at a Single Slit