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MHT CET 2023 (11 May, Shift 2) · Splitting & Merging of Drops

Splitting & Merging of Drops question from MHT CET 2023 (11 May, Shift 2)

Q35MHT CET 2023 · 11 MAY · SHIFT 2Medium

Splitting & Merging of Drops

A liquid drop of radius 'RR' is broken into 'nn' identical small droplets. The work done is [T = surface tension of the liquid]

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Answer: (b)

  1. nr3=R3⇒r=R n−1/3n r^3 = R^3 \Rightarrow r = R\, n^{-1/3}.
  2. Final area =n⋅4πR2n−2/3=4πR2n1/3= n \cdot 4\pi R^2 n^{-2/3} = 4\pi R^2 n^{1/3}
  3. W=T ΔA=4πR2(n1/3−1)TW = T\,\Delta A = 4\pi R^2 \left(n^{1/3} - 1\right) T
  4. So the answer is (b).
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