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MHT CET 2025 (21 Apr, Shift 1) · Force due to Surface Tension

Force due to Surface Tension question from MHT CET 2025 (21 Apr, Shift 1)

Q7MHT CET 2025 · 21 APR · SHIFT 1Difficult

Force due to Surface Tension

A liquid drop of volume V is placed on the surface of glass plate. Then another glass plate is placed on it such that liquid forms a thin layer of area A between the surfaces of two plates. To separate the plates a force F has to be applied normal to the surfaces. The surface tension of the liquid is

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Answer: (b)

Thickness of layer $t = \dfrac{V}{A}$ .
Force to separate plates: $F = \dfrac{2AT}{t} = \dfrac{2A^2 T}{V}$ .
$T = \dfrac{FV}{2A^2}$ . So the answer is (b).

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