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NEET 1994 (AIPMT) · Energy in SHM

Energy in SHM question from NEET 1994 (AIPMT)

Q84NEET 1994 · AIPMTEasy

Energy in SHM

A loaded vertical spring executes S.H.M. with a time period of $4\text{ sec}$ . The difference between the kinetic energy and potential energy of this system varies with a period of

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Answer: (a)

$KE = E\cos^2\omega t$ , $PE = E\sin^2\omega t$
$KE - PE = E\cos 2\omega t$ , which has period $\frac{T}{2}$ .
$\frac{T}{2} = \frac{4}{2} = 2$ s
So the answer is (a) 2 sec.

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