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MHT CET 2026 (20 May, Shift 1) · Motional EMF

Motional EMF question from MHT CET 2026 (20 May, Shift 1)

Q5MHT CET 2026 · 20 MAY · SHIFT 1Medium

Motional EMF

A long metal rod of length 'L' completes the circuit. The area of the coil is perpendicular to magnetic field 'B'. Total resistance of the circuit is 'R'. The force needed to move the rod in the direction as shown with constant speed 'V' is

Figure

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Answer: (c)

  1. Emf ε=BLV\varepsilon = BLV, current I=BLVRI = \frac{BLV}{R}.
  2. Magnetic force on the rod opposes motion: Fm=BIL=B2L2VRF_m = BIL = \frac{B^2L^2V}{R}.
  3. Constant speed needs an equal applied force: F=B2L2VRF = \frac{B^2L^2V}{R}. So the answer is (c).
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