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MHT CET 2025 (26 Apr, Shift 2) · Motional EMF

Motional EMF question from MHT CET 2025 (26 Apr, Shift 2)

Q17MHT CET 2025 · 26 APR · SHIFT 2Medium

Motional EMF

A long rectangular conducting loop of width ' ll ', mass ' mm ' and resistance ' RR ' is placed partly in a perpendicular magnetic field ' B '. It is pushed downwards with velocity ' VV ' so that it may continue to fall freely. The velocity ' VV ' is

Figure

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Answer: (c)

  1. emf e=BlVe = BlV, current I=BlVRI = \dfrac{BlV}{R}.
  2. Magnetic force F=BIl=B2l2VRF = BIl = \dfrac{B^2l^2V}{R} opposes the fall.
  3. For uniform motion: B2l2VR=mg\dfrac{B^2l^2V}{R} = mg
  4. So the answer is (c) V=mgRB2l2V = \dfrac{mgR}{B^2l^2}.
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