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MHT CET 2025 (26 Apr, Shift 2) · Motional EMF

Motional EMF question from MHT CET 2025 (26 Apr, Shift 2)

Q17MHT CET 2025 · 26 APR · SHIFT 2Medium

Motional EMF

A long rectangular conducting loop of width ' $l$ ', mass ' $m$ ' and resistance ' $R$ ' is placed partly in a perpendicular magnetic field ' B '. It is pushed downwards with velocity ' $V$ ' so that it may continue to fall freely. The velocity ' $V$ ' is

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Answer: (c)

emf $e = BlV$ , current $I = \dfrac{BlV}{R}$ .
Magnetic force $F = BIl = \dfrac{B^2l^2V}{R}$ opposes the fall.
For uniform motion: $\dfrac{B^2l^2V}{R} = mg$
So the answer is (c) $V = \dfrac{mgR}{B^2l^2}$ .

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