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JEE Main 2022 (25 Jun, Shift 2) · Ampere's Law, Cylinders, Solenoid & Toroid

Ampere's Law, Cylinders, Solenoid & Toroid question from JEE Main 2022 (25 Jun, Shift 2)

Q34JEE Main 2022 · 25 JUN · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid

A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of magnetic field will be equal to

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Answer: (a)

  1. B=μ0nI∝nIB = \mu_0 n I \propto nI.
  2. B′=μ0(n2)(2I)=BB' = \mu_0 \left(\dfrac{n}{2}\right)(2I) = B.
  3. So the answer is (a) BB.
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