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MHT CET 2024 (9 May, Shift 2) · Ampere's Law, Cylinders, Solenoid & Toroid

Ampere's Law, Cylinders, Solenoid & Toroid question from MHT CET 2024 (9 May, Shift 2)

Q21MHT CET 2024 · 9 MAY · SHIFT 2Easy

Ampere's Law, Cylinders, Solenoid & Toroid

A long solenoid carrying a current produces magnetic field B along its axis. If the number of turns per cm are tripled and the current is made (14)\left(\frac{1}{4}\right)th then the new value of magnetic field will be

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Answer: (c)

  1. B=μ0nI∝nIB = \mu_0 n I \propto nI.
  2. B′=μ0(3n)(I4)=34BB' = \mu_0 (3n)\left(\dfrac{I}{4}\right) = \dfrac{3}{4}B.
  3. So the answer is (c) 3B4\dfrac{3B}{4}.
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