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NEET 2016 (Phase 1) · Self-Inductance & Energy

Self-Inductance & Energy question from NEET 2016 (Phase 1)

Q77NEET 2016 · PHASE 1Easy

Self-Inductance & Energy

A long solenoid has 1000 turns. When a current of 4 A flows through it, the magnetic flux linked with each turn of the solenoid is 4 ×10−3\times 10^{-3} Wb. The self-inductance of the solenoid is

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Answer: (b)

  1. L=NϕIL = \frac{N\phi}{I}
  2. L=1000×4×10−34L = \frac{1000 \times 4\times10^{-3}}{4}
  3. L=1 HL = 1\text{ H}, so the answer is (b).
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