Student Login

Home›Chapters›Electromagnetic Induction PYQs›Self-Inductance & Energy›Question 81

NEET 2008 (AIPMT) · Self-Inductance & Energy

Self-Inductance & Energy question from NEET 2008 (AIPMT)

Q81NEET 2008 · AIPMTEasy

Self-Inductance & Energy

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 $\times$ 10 $-$ 3 Wb. The self-inductance of the solenoid is

Show answer and solution

Answer: (a)

$L = \frac{N\phi}{I}$
$L = \frac{500 \times 4\times10^{-3}}{2}$
$L = 1.0\text{ H}$ , so the answer is (a).

Report a mistake

More questions on Self-Inductance & Energy

When the current changes from +2 A to -2 A in 0.05 second, an e.m.f. of 8 V is inducted…JEE Main 2003 (AIEEE)
For a coil having L = 2 mH, current flow through it is I = t² e-t then, the time at which…NEET 2001 (AIPMT)
The current I in an A.C. circuit with inductance coil varies with time according to the…NEET 1994 (AIPMT)
What is the self-inductance of a coil which produces 5 V when the current changes from 3…NEET 1993 (AIPMT)
If N is the number of turns in a coil, the value of self inductance varies asNEET 1993 (AIPMT)
If the number of turns per unit length of a coil of solenoid is doubled, the…NEET 1991 (AIPMT)
A 100 millihenry coil carries a current of 1 A. Energy stored in its magnetic field isNEET 1991 (AIPMT)
The current in self inductance L = 40 mH is to be increased uniformly from 1 amp to 11…NEET 1990 (AIPMT)