A long straight wire of length 2 m and mass 250 g is suspended horizontally in a uniform horizontal magnetic field of 0.7 T. The amount of current flowing through the wire will be (g = 9.8 m s⁻²): (a) 2.45 A (b) 2.25 A (c) 2.75 A (d) 1.75 A

Answer: (d). Magnetic force balances weight: BIL = mg. I = mg/BL = (0.25 × 9.8)/(0.7 × 2) = 1.75 A So the answer is (d) 1.75 A.

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Force on Current-Carrying Conductors

A long straight wire of length $2\text{ m}$ and mass $250\text{ g}$ is suspended horizontally in a uniform horizontal magnetic field of $0.7\text{ T}$ . The amount of current flowing through the wire will be $\left(g = 9.8\text{ m s}^{-2}\right)$ :

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Answer: (d)

Magnetic force balances weight: $BIL = mg$ .
$I = \dfrac{mg}{BL} = \dfrac{0.25 \times 9.8}{0.7 \times 2} = 1.75\text{ A}$
So the answer is (d) 1.75 A.

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