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MHT CET 2025 (25 Apr, Shift 1) · Impulse & Momentum Conservation

Impulse & Momentum Conservation question from MHT CET 2025 (25 Apr, Shift 1)

Q5MHT CET 2025 · 25 APR · SHIFT 1Easy

Impulse & Momentum Conservation

A machine gun fires a bullet of mass 35 gram with a speed of 600 m/s600\text{ m/s}. The person holding the gun can extract a maximum force of 147 N on it. The number of bullets that can be fired from the gun per second is

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Answer: (c)

  1. Force on the gun =n×mv= n \times mv (nn = bullets per second).
  2. mv=0.035×600=21 N smv = 0.035 \times 600 = 21\text{ N s}
  3. n=14721=7n = \frac{147}{21} = 7
  4. So the answer is (c) 7.
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