Physics Circle home Student Login

Home›Chapters›Laws of Motion PYQs›Impulse & Momentum Conservation›Question 3

MHT CET 2026 (17 Apr, Shift 2) · Impulse & Momentum Conservation

Impulse & Momentum Conservation question from MHT CET 2026 (17 Apr, Shift 2)

Q3MHT CET 2026 · 17 APR · SHIFT 2Easy

Impulse & Momentum Conservation

A machine gun fires a bullet of mass 40g with a speed of 600600 ms−1^{-1}. The person holding the gun can bare maximum force of 168N on it. The number of bullets that can be fired from the gun per second is

Show answer and solution

Answer: (b)

  1. Force on the gun =n×mv= n \times mv (nn = bullets per second).
  2. mv=0.04×600=24 N smv = 0.04 \times 600 = 24\text{ N s}
  3. n=16824=7n = \frac{168}{24} = 7
  4. So the answer is (b) 7.
Report a mistake

More questions on Impulse & Momentum Conservation