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MHT CET 2023 (14 May, Shift 2) · Impulse & Momentum Conservation

Impulse & Momentum Conservation question from MHT CET 2023 (14 May, Shift 2)

Q12MHT CET 2023 · 14 MAY · SHIFT 2Easy

Impulse & Momentum Conservation

A machine gun fires bullets of mass $30\text{ g}$ with velocity of $1000\text{ m/s}$ . The man holding the gun can exert a maximum force of $300\text{ N}$ on it. How many bullets can he fire per second at most?

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Answer: (c)

Force on gun $F = n\,m v$ , where $n$ = bullets per second.
$n = \frac{F}{mv} = \frac{300}{0.03 \times 1000} = \frac{300}{30}$
$n = 10$ bullets per second.
So the answer is (c) 10.

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