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MHT CET 2025 (26 Apr, Shift 1) · Magnetic Flux & Faraday's Law

Magnetic Flux & Faraday's Law question from MHT CET 2025 (26 Apr, Shift 1)

Q24MHT CET 2025 · 26 APR · SHIFT 1Easy

Magnetic Flux & Faraday's Law

A magnetic field 4×10−2 T4 \times 10^{-2}\text{ T} acts at right angles to a coil of area 100 cm2100\text{ cm}^{2} with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in time ' tt '. The value of ' tt ' is

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Answer: (c)

  1. Removing the coil takes flux from NBANBA to 00: e=NBAte = \frac{NBA}{t}.
  2. t=NBAe=50×4×10−2×10−20.1t = \frac{NBA}{e} = \frac{50\times 4\times 10^{-2}\times 10^{-2}}{0.1}
  3. t=0.020.1=0.2t = \frac{0.02}{0.1} = 0.2 s
  4. So the answer is (c) 0.2 second.
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