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NEET 1991 (AIPMT) · Magnetic Flux & Faraday's Law

Magnetic Flux & Faraday's Law question from NEET 1991 (AIPMT)

Q89NEET 1991 · AIPMTEasy

Magnetic Flux & Faraday's Law

A magnetic field of 2×10−2 T2 \times 10^{-2}\text{ T} acts at right angles to a coil of area 100 cm2100\text{ cm}^{2}, with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in tt sec. The value of tt is

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Answer: (b)

  1. t=NBAet = \frac{NBA}{e}
  2. t=50×2×10−2×10−20.1=0.1t = \frac{50\times 2\times 10^{-2}\times 10^{-2}}{0.1} = 0.1 s
  3. So the answer is (b) 0.10.1 s.
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