A magnetic intensity of 500 A/m, produces a magnetic flux of 2.4 × 10⁻⁵ Wb in an iron bar of cross- sectional area 0.4 cm². The magnetic permeability of the iron bar is (a) 2.4 × 10⁻³ N/m² (b) 1.2 × 10⁻³ N/m² (c) 2.4 × 10⁻⁴ N/m² (d) 1.2 × 10⁻⁴ N/m²

Answer: (b). B = Φ/A = 2.4×10⁻⁵0.4×10⁻⁴ = 0.6 T μ = B/H = (0.6)/(500) = 1.2×10⁻³ (SI unit T m/A, i.e. N/A ²; the 'N/m ² ' in the options is a misprint). So the answer is (b).

A magnetic intensity of 500 A/m, produces a magnetic flux of 2.4 ×… | MHT CET 2024 (4 May, Shift 2)

Q22MHT CET 2024 · 4 MAY · SHIFT 2Easy

Magnetisation: B, H, M, χ & μ

A magnetic intensity of $500\text{ A/m}$ , produces a magnetic flux of $2.4 \times 10^{-5}\text{ Wb}$ in an iron bar of cross- sectional area $0.4\text{ cm}^2$ . The magnetic permeability of the iron bar is

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Answer: (b)

$B = \dfrac{\Phi}{A} = \dfrac{2.4\times10^{-5}}{0.4\times10^{-4}} = 0.6\text{ T}$
$\mu = \dfrac{B}{H} = \dfrac{0.6}{500} = 1.2\times10^{-3}$ (SI unit T m/A, i.e. N/A $^2$ ; the 'N/m $^2$ ' in the options is a misprint).
So the answer is (b).

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Magnetisation: B, H, M, χ & μ question from MHT CET 2024 (4 May, Shift 2)

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