A magnetizing field of 5000 A/m produces a magnetic flux of 4 × 10⁻⁵ Wb in an iron rod of cross- sectional area 0.4 cm². The permeabilit of the rod in Wb/A-m, is (a) 4 × 10⁻⁶ (b) 1 × 10⁻³ (c) 2 × 10⁻⁴ (d) 3 × 10⁻⁵

Answer: (c). B = Φ/A = 4×10⁻⁵0.4×10⁻⁴ = 1 T μ = B/H = 1/5000 = 2×10⁻⁴ Wb/A-m So the answer is (c).

A magnetizing field of 5000 A/m produces a magnetic flux of 4 × 10⁻⁵… | MHT CET 2019 (3 May, Shift 1)

Q44MHT CET 2019 · 3 MAY · SHIFT 1Easy

Magnetisation: B, H, M, χ & μ

A magnetizing field of $5000\text{ A/m}$ produces a magnetic flux of $4 \times 10^{-5}\text{ Wb}$ in an iron rod of cross- sectional area $0.4\text{ cm}^2$ . The permeabilit of the rod in Wb/A-m, is

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Answer: (c)

$B = \dfrac{\Phi}{A} = \dfrac{4\times10^{-5}}{0.4\times10^{-4}} = 1\text{ T}$
$\mu = \dfrac{B}{H} = \dfrac{1}{5000} = 2\times10^{-4}\text{ Wb/A-m}$
So the answer is (c).

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Magnetisation: B, H, M, χ & μ question from MHT CET 2019 (3 May, Shift 1)

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