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NEET 2010 (AIPMT, Prelims) · Newton's Law of Gravitation

Newton's Law of Gravitation question from NEET 2010 (AIPMT, Prelims)

Q22NEET 2010 · AIPMT · PRELIMSMedium

Newton's Law of Gravitation

A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be

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Answer: (b)

  1. No external force, so momentum is conserved: 50v=0.5×2⇒v=0.0250v = 0.5 \times 2 \Rightarrow v = 0.02 m/s upward for the man.
  2. No gravity, so the stone moves uniformly: t=102=5t = \frac{10}{2} = 5 s.
  3. Man rises 0.02×5=0.10.02 \times 5 = 0.1 m, so his height =10+0.1=10.1= 10 + 0.1 = 10.1 m.
  4. So the answer is (b) 10.1 m.
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