Physics Circle home Student Login

Home›Chapters›Rotational Motion PYQs›Angular Momentum & its Conservation›Question 18

MHT CET 2025 (26 Apr, Shift 2) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from MHT CET 2025 (26 Apr, Shift 2)

Q18MHT CET 2025 · 26 APR · SHIFT 2Medium

Angular Momentum & its Conservation

A man standing on a turn-table is rotating at a certain angular frequency with his arms outstretched. He suddenly folds his arms. If his moment of inertia with folded arms is 75%75\% of that with outstretched arms, then his rotational kinetic energy will

Show answer and solution

Answer: (a)

  1. No external torque, so LL is constant and K=L22I∝1IK=\frac{L^2}{2I}\propto\frac1I.
  2. I′=0.75I⇒K′=K0.75=43KI'=0.75I\Rightarrow K'=\frac{K}{0.75}=\frac43K
  3. Increase =13=33.3%=\frac13=33.3\%
  4. So the answer is (a) increase by 33.3%.
Report a mistake

More questions on Angular Momentum & its Conservation