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NEET 2003 (AIPMT) · Motion Under Gravity

Motion Under Gravity question from NEET 2003 (AIPMT)

Q56NEET 2003 · AIPMTMedium

Motion Under Gravity

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given g = 9.8 m/s2)

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Answer: (a)

For more than two balls in the air, each ball must stay up longer than two intervals: $T > 2 \times 2 = 4$ s
Time of flight $T = \frac{2u}{g} > 4 \Rightarrow u > 2g = 19.6$ m/s
So the answer is (a) more than 19.6 m/s.

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