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NEET 2003 (AIPMT) · Apparent Weight & Lift

Apparent Weight & Lift question from NEET 2003 (AIPMT)

Q19NEET 2003 · AIPMTEasy

Apparent Weight & Lift

A man weight 80 kg. He stands on a weighting scale in a lift which is moving upwards with a uniform acceleration of 5 m/s2. What would be the reading on the scale? (g = 10 m/s2)

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Answer: (d)

  1. Lift accelerating up: N=m(g+a)N = m(g + a).
  2. N=80×(10+5)=1200N = 80 \times (10 + 5) = 1200 N
  3. So the answer is (d) 1200 N.
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