Physics Circle home Student Login

Home›Chapters›Oscillations PYQs›Energy in SHM›Question 11

MHT CET 2026 (11 Apr, Shift 2) · Energy in SHM

Energy in SHM question from MHT CET 2026 (11 Apr, Shift 2)

Q11MHT CET 2026 · 11 APR · SHIFT 2Medium

Energy in SHM

A mass 0.40.4 kg performs S.H.M. with a frequency 16π\frac{16}{\pi} Hz. At a certain displacement it has kinetic energy 22 J and potential energy 1.21.2 J. The amplitude of oscillation is

Show answer and solution

Answer: (a)

  1. ω=2πf=2π×16π=32\omega = 2\pi f = 2\pi \times \frac{16}{\pi} = 32 rad/s
  2. E=KE+PE=2+1.2=3.2E = KE + PE = 2 + 1.2 = 3.2 J
  3. E=12mω2A2⇒3.2=12(0.4)(1024)A2=204.8A2E = \frac{1}{2}m\omega^2A^2 \Rightarrow 3.2 = \frac{1}{2}(0.4)(1024)A^2 = 204.8A^2
  4. A2=0.015625⇒A=0.125A^2 = 0.015625 \Rightarrow A = 0.125 m
  5. So the answer is (a) 0.125 m.
Report a mistake

More questions on Energy in SHM