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MHT CET 2026 (11 Apr, Shift 2) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from MHT CET 2026 (11 Apr, Shift 2)

Q4MHT CET 2026 · 11 APR · SHIFT 2Easy

Periodic Motion & SHM Basics

A mass attached to a spring performs S.H.M. whose displacement is x=3×10−3cos⁡2πtx = 3 \times 10^{-3}\cos 2\pi t m. The time taken to obtain maximum speed for the first time is (in s)

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Answer: (c)

  1. ω=2π\omega = 2\pi, so T=1 sT = 1\ \text{s}.
  2. x=Acos⁡2πtx = A\cos 2\pi t starts at the extreme position (x=Ax = A) at t=0t = 0.
  3. Speed is maximum at the mean position, reached after T4=14 s\frac{T}{4} = \frac{1}{4}\ \text{s}.
  4. So the answer is (c) 14\frac{1}{4}.
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