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MHT CET 2019 (3 May, Shift 1) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2019 (3 May, Shift 1)

Q45MHT CET 2019 · 3 MAY · SHIFT 1Medium

Centripetal Acceleration & Force

A mass is whirled in a circular path with constant angular velocity and its linear velocity is $v$ . If the string is now halved keeping the angular momentum same, the linear velocity is

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Answer: (a)

Angular momentum $L = mvr$ is kept the same.
String halved: $r' = \frac{r}{2}$ , so $m v' \frac{r}{2} = mvr$ .
$v' = 2v$
So the answer is (a) $2v$ .

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