A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when: (a) the wire is horizontal (b) inclined at an angle of 60° from vertical (c) the mass is at the lowest point (d) the mass is at the highest point

Answer: (c). Tension at angle θ from the lowest point: T = mv²/r + mgcos θ. At the lowest point both v and cos θ are maximum, so Tmax = mg + mv²/r. So the answer is (c) the mass is at the lowest point.

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Circular Motion (Related PYQs)

A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:

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Answer: (c)

Tension at angle $\theta$ from the lowest point: $T = \frac{mv^2}{r} + mg\cos\theta$ .
At the lowest point both $v$ and $\cos\theta$ are maximum, so $T_{max} = mg + \frac{mv^2}{r}$ .
So the answer is (c) the mass is at the lowest point.

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