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JEE Main 2014 · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from JEE Main 2014

Q69JEE Main 2014Medium

Rotational Kinematics & Dynamics

A mass ′m′'m' is supported by a massless string wound around a uniform hollow cylinder of mass mm and radius R.R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release?

Figure

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Answer: (b)

  1. Hollow cylinder: I=mR2I = mR^2, so T=IaR2=maT = \frac{I a}{R^2} = ma.
  2. Block: mg−T=ma⇒mg=2mamg - T = ma \Rightarrow mg = 2ma
  3. So the answer is (b) g2\frac{g}{2}.
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