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MHT CET 2023 (13 May, Shift 2) · Spring Systems

Spring Systems question from MHT CET 2023 (13 May, Shift 2)

Q53MHT CET 2023 · 13 MAY · SHIFT 2Medium

Spring Systems

A mass MM is suspended from a light spring. An additional mass M1M_1 added extends the spring further by a distance xx. Now, the combined mass will oscillate on the spring with period T=T =

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Answer: (b)

  1. Extra mass M1M_1 gives extra extension xx: k=M1gxk = \frac{M_1 g}{x}.
  2. Total mass M+M1M + M_1: T=2πM+M1k=2π(M+M1)xM1gT = 2\pi\sqrt{\frac{M+M_1}{k}} = 2\pi\sqrt{\frac{(M+M_1)x}{M_1 g}}
  3. So the answer is (b).
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