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NEET 2011 (AIPMT, Mains) · Thermodynamic Processes

Thermodynamic Processes question from NEET 2011 (AIPMT, Mains)

Q240NEET 2011 · AIPMT · MAINSMedium

Thermodynamic Processes

A mass of diatomic gas (γ=1.4)(\gamma = 1.4) at a pressure of 2 atmospheres is compressed adiabatically so that its temperature rises from 27oC to 927oC. The pressure of the gas in the final state is

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Answer: (d)

  1. Adiabatic: P∝Tγ/(γ−1)=T1.4/0.4=T3.5P \propto T^{\gamma/(\gamma-1)} = T^{1.4/0.4} = T^{3.5}.
  2. T1=300 KT_1 = 300\ \text{K}, T2=1200 KT_2 = 1200\ \text{K}, ratio =4= 4.
  3. P2=2×43.5=2×128=256 atmP_2 = 2 \times 4^{3.5} = 2 \times 128 = 256\ \text{atm}
  4. So the answer is (d) 256 atm.
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