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MHT CET 2024 (4 May, Shift 1) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from MHT CET 2024 (4 May, Shift 1)

Q20MHT CET 2024 · 4 MAY · SHIFT 1Medium

Force on Current-Carrying Conductors

A massless square loop of wire of resistance ' RR ' supporting a mass ' M ' hangs vertically with one of its sides in a uniform magnetic field ' B ' directed outwards in the shaded region. A d.c. voltage ' V ' is applied to the loop. For what value of ' VV ' the magnetic force will exactly balance the weight of the supporting mass ' M '? (side of loop = L, g=g = acceleration due to gravity)

Figure

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Answer: (c)

  1. Only the top side (length LL) is in the field; forces on the vertical sides cancel.
  2. Balance: ILB=MgI L B = Mg with I=VRI = \frac{V}{R}
  3. VRLB=Mg⇒V=MgRLB\frac{V}{R}LB = Mg \Rightarrow V = \frac{MgR}{LB}
  4. So the answer is (c) MgRLB\frac{MgR}{LB}.
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