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JEE Main 2004 (AIEEE) · Rotating Conductors & AC Generator

Rotating Conductors & AC Generator question from JEE Main 2004 (AIEEE)

Q34JEE Main 2004 · AIEEEEasy

Rotating Conductors & AC Generator

A metal conductor of length 1 m1\text{ m} rotates vertically about one of its ends at angular velocity 55 radians per second. If the horizontal component of earth's magnetic field is 0.2×10−4 T,0.2 \times 10^{-4}\text{ T}, then the e.m.f.e.m.f. developed between the two ends of the conductor is

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Answer: (b)

  1. Rotating about one end in a vertical plane, the rod cuts BHB_H: e=12BHωl2e = \tfrac{1}{2}B_H\omega l^2
  2. e=12×0.2×10−4×5×1=5×10−5 Ve = \tfrac{1}{2} \times 0.2 \times 10^{-4} \times 5 \times 1 = 5 \times 10^{-5}\text{ V}
  3. So the answer is (b) 50 μ50\ \muV.
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