Physics Circle home Student Login

Home›Chapters›Electromagnetic Induction PYQs›Rotating Conductors & AC Generator›Question 21

MHT CET 2023 (13 May, Shift 2) · Rotating Conductors & AC Generator

Rotating Conductors & AC Generator question from MHT CET 2023 (13 May, Shift 2)

Q21MHT CET 2023 · 13 MAY · SHIFT 2Easy

Rotating Conductors & AC Generator

A metal disc of radius RR rotates with an angular velocity ω\omega about an axis perpendicular to its plane passing through its centre in a magnetic field of induction BB acting perpendicular to the plane of the disc. The magnitude of induced emf between the rim and axis of the disc is

Show answer and solution

Answer: (d)

  1. Each radius of the disc behaves like a rod rotating about one end.
  2. e=∫0RBωx dx=12BωR2e = \int_0^R B\omega x\,dx = \tfrac{1}{2}B\omega R^2
  3. So the answer is (d) BR2ω2\dfrac{BR^2\omega}{2}.
Report a mistake

More questions on Rotating Conductors & AC Generator