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MHT CET 2024 (15 May, Shift 2) · Rotating Conductors & AC Generator

Rotating Conductors & AC Generator question from MHT CET 2024 (15 May, Shift 2)

Q11MHT CET 2024 · 15 MAY · SHIFT 2Easy

Rotating Conductors & AC Generator

A metal disc of radius R rotates with an angular velocity ω\omega about an axis perpendicular to its plane passing through its centre in a magnetic field of induction B acting perpendicular to the plane of the disc. The induced e.m.f. between the rim and axis of the disc is

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Answer: (d)

  1. The disc acts like many radial rods from axis to rim, all in parallel.
  2. Each radius gives e=∫0RBωx dx=12BωR2e = \int_0^R B\omega x\,dx = \tfrac{1}{2}B\omega R^2
  3. So the answer is (d) BR2ω2\dfrac{BR^2\omega}{2}.
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