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MHT CET 2026 (14 May, Shift 2) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2026 (14 May, Shift 2)

Q12MHT CET 2026 · 14 MAY · SHIFT 2Difficult

Thermometry & Thermal Expansion

A metal rod (A) of length 2020 cm expands by 0.0750.075 cm when its temperature changes from 0∘0^{\circ}C to 100∘100^{\circ} C. Another metal rod (B) of different metal of same length expands by 0.0450.045 cm for same temperature change. A third rod of same length is composed of 2 parts, one of metal A and another of metal B. For same temperature change, this rod expands by 0.0600.060 cm. The portion made of metal A has the length

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Answer: (b)

  1. Expansion per cm for 100∘100^\circC: A gives 0.075/20=0.003750.075/20 = 0.00375, B gives 0.045/20=0.002250.045/20 = 0.00225.
  2. Let A part be xx: 0.00375x+0.00225(20−x)=0.0600.00375x + 0.00225(20 - x) = 0.060
  3. 0.0015x=0.015⇒x=100.0015x = 0.015 \Rightarrow x = 10 cm
  4. So the answer is (b) 10 cm.
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