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MHT CET 2020 (19 Oct, Shift 2) · Elastic Potential Energy

Elastic Potential Energy question from MHT CET 2020 (19 Oct, Shift 2)

Q8MHT CET 2020 · 19 OCT · SHIFT 2Easy

Elastic Potential Energy

A metal rod has length, cross-sectional area and Young's modulus as $L, A$ and $Y$ , respectively. If the elongation in the rod produced is $\ell$ , then work done is proportional to

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Answer: (d)

Work done $W = \dfrac{1}{2}F\ell$ with $F = \dfrac{YA\ell}{L}$ .
$W = \dfrac{YA\ell^2}{2L} \propto \ell^2$
So the answer is (d) $\ell^2$ .

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