A metal rod having coefficient of linear expansion 2 × 10⁻⁵/ is 0.75 m long at 45. When the temperature rises to 65, the increase in length of the rod will be (a) 3.0 mm (b) 0.75 mm (c) 0.30 mm (d) 0.15 mm

Answer: (c). Δ L=LαΔ T Δ L=0.75× 2×10⁻⁵× 20=3×10⁻⁴ m So the answer is (c) 0.30 mm.

A metal rod having coefficient of linear expansion 2 × 10⁻⁵/ is 0.75… | MHT CET 2024 (11 May, Shift 2)

Q23MHT CET 2024 · 11 MAY · SHIFT 2Easy

Thermometry & Thermal Expansion

A metal rod having coefficient of linear expansion $2 \times 10^{-5}/^\circ\text{C}$ is 0.75 m long at $45^\circ\text{C}$ . When the temperature rises to $65^\circ\text{C}$ , the increase in length of the rod will be

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Answer: (c)

$\Delta L=L\alpha\Delta T$
$\Delta L=0.75\times 2\times10^{-5}\times 20=3\times10^{-4}$ m
So the answer is (c) 0.30 mm.

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Thermometry & Thermal Expansion question from MHT CET 2024 (11 May, Shift 2)

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