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MHT CET 2026 (16 Apr, Shift 1) · Motional EMF

Motional EMF question from MHT CET 2026 (16 Apr, Shift 1)

Q6MHT CET 2026 · 16 APR · SHIFT 1Medium

Motional EMF

A metal rod of length 'L' completes the circuit as shown. The area of the circuit is perpendicular to magnetic field 'B'. Total resistance of the circuit is 'R'. The force needed to move the rod in the direction as shown with constant speed 'V' is

Figure

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Answer: (b)

  1. Emf ε=BLV\varepsilon = BLV, current I=BLVRI = \frac{BLV}{R}.
  2. Opposing magnetic force Fm=BIL=B2L2VRF_m = BIL = \frac{B^2L^2V}{R}.
  3. For constant speed, applied force F=B2L2VRF = \frac{B^2L^2V}{R}. So the answer is (b).
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