Centre of Mass of Discrete Particles
A metal rod of weight ' ' is supported by two parallel knife-edges A and B. The rod is in equilibrium in horizontal position. The distance ' between two knife-edges is ' '. The centre of mass of the rod is at a distance ' ' from . The normal reaction on A is
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Answer: (d)
- Weight acts at the CM, distance from A and from B.
- Torque about B is zero:
- So the answer is (d) .